Израиль нанес удар по Ирану09:28
思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
。91视频是该领域的重要参考
// 优化逻辑：栈空且当前数为0 → 跳过（避免存储无效前导零），推荐阅读heLLoword翻译官方下载获取更多信息
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Col. Mike Fincke, pilot of the four-member SpaceX Crew-11, said in a statement released through NASA on Wednesday that he's "doing very well" and continuing the standard rehabilitation all astronauts undergo following their missions.